The sum of 2x, 3x, 4x terms of an AP are s1, s 2, s3 respectively. Prove that s3= 3 (s2- s1).
TheRealSherlock:
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since the formula of sun of nth term in A.P is n/2{2a+(n-1)d}nowS1=n/2{2a+(n-1)d}S2=2n/2{2a+(2n-1)d}S3=3n/2{2a+(3n-1)d}S2-S1=n/2{2a+(3n-1)d}
therefore3(S2-S1)=3n/2{2a+(3n-1)d}=S3
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therefore3(S2-S1)=3n/2{2a+(3n-1)d}=S3
hpe i helped u plz mark as brainiest answer plz
there is gaps in between them i cannot edit
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