Math, asked by MausamRangare84, 18 days ago

A triangle and a parallelogram have the same base and the same area. If the side
the triangle are 26 cm, 28 cm and 30 em, and the parallelogram stands on the
28 cm, find the height of the parallelogram.​

Answers

Answered by sanapoddar
1

Answer:

12cm

Step-by-step explanation:

It is given that a triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 26 cm, 28 cm, and 30 cm, and the parallelogram stands on the base 28 cm, we have found that the height of the parallelogram is 12 cm.

Answered by Rizakhan49
83

Solution :-

a = 26

b = 28 ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎s = 26 + 28 + 30/2

c = 30

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎= 84/2

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎= 42

Area of = √s (s – a) (s – b) (s – c)

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎= √42 (42 – 26) (42 – 28) (42 – 30)

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎= √42 × 16 × 14 × 12

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎= 336cm²

Now area of parallelogram

→ base × height

→ 28 × height

Area = 336cm²

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎= 28 × height = 336cm²

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎= height = 1/28 × 336

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎= 12cm Ans.

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