A triangle and a parallelogram have the same base and the same area. If the side
the triangle are 26 cm, 28 cm and 30 em, and the parallelogram stands on the
28 cm, find the height of the parallelogram.
Answers
Answer:
12cm
Step-by-step explanation:
It is given that a triangle and a parallelogram have the same base and the same area. If the sides of the triangle are 26 cm, 28 cm, and 30 cm, and the parallelogram stands on the base 28 cm, we have found that the height of the parallelogram is 12 cm.
Solution :-
a = 26
b = 28 s = 26 + 28 + 30/2
c = 30
= 84/2
= 42
Area of ∆ = √s (s – a) (s – b) (s – c)
= √42 (42 – 26) (42 – 28) (42 – 30)
= √42 × 16 × 14 × 12
= 336cm²
Now area of parallelogram
→ base × height
→ 28 × height
Area = 336cm²
= 28 × height = 336cm²
= height = 1/28 × 336
= 12cm Ans.