Question

A triangle and a parallelogram lies on same base having equal area and Parallelogram lies on 15cm then find height of Parallelogram and area of Parallelogram​

Answer 1

Answer:

If a triangle and parallelogram are on the same base and have the same altitude, the area of the triangle will be half that of the parallelogram. If they have same altitude, they will lie between the same parallels. Hence the area of the triangle will be equal to half that of the parallelogram.

Explanation:

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Answer 2

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We know,

The area of a triangle is:

A = [s(s-a)(s-b)(s-c)]^1/2

=[21(21-13)(21-14)(21-15)]^1/2

=[21×8×7×6]^1/2

=[7056]^1/2

=84 cm^2

Now,

The area of the triangle and parallelogram is same and both have same bas i.e. 14 cm.

So,

The area of parallelogram is also:

A=84 cm^2

or, b×h=84 [As area of parallelogram = b×h]

or, 14×h=84

or,h = 84/14

Hence, h = 6cm

Thus, the required height of the parallelogram is 6cm.