A triangle has sides 5 inches,12 inches and 13 inches.A rectangle equal in area to that of the triangle has a width of 4 inches.what is the perimeter of thr rectangle un inches??
mariabutt60:
plz ans this
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by pythagoras theorem,
a^2 = b^2 + c^2
13^2 = 169
12^2 + 5^2 = 144 + 25 = 169
hence it is a right angled triangle.so h = 5 inches and b = 12 inches or vise versa
area of triangle = 1/2 × b × h
= 1/2 × 12 × 5
= 30 inches^2
area of rect. =lb
l × 4 = 30
l = 30 /4 = 7.5 inches
perimeter of rect = 2(l+b)
= 2(7.5 + 4)
= 2(11.5) = 23 inches
a^2 = b^2 + c^2
13^2 = 169
12^2 + 5^2 = 144 + 25 = 169
hence it is a right angled triangle.so h = 5 inches and b = 12 inches or vise versa
area of triangle = 1/2 × b × h
= 1/2 × 12 × 5
= 30 inches^2
area of rect. =lb
l × 4 = 30
l = 30 /4 = 7.5 inches
perimeter of rect = 2(l+b)
= 2(7.5 + 4)
= 2(11.5) = 23 inches
why we will use Pythagoras theorem??
to prove that it is an right angled triangle
if we dont use it then we may not be able to know what to be used as h and b
am confused why we will take 13 as hypothesis??
because longest side will always be the hypotenuse
ok thank u so much ☺
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