Question

a triangle having a perimeter 56 and its sides are 2x, 2x+3 and 2x+5 find the length of 3 sides

Answer 1

According to the given conditions,
2x + (2x+3)+(2x+5) = 56
=) 6x + 8 = 56
=) 6x = 56-8
=) x = 48/6
=) x = 8
Therefore the sides of the triangle are:
2x = 2*8 = 16
2x+3 = 2*8+3 = 19
2x + 5 = 2*8+5 = 21

Hope it helped!

Answer 2

Perimeter of a rectangle=a+b+c= 56
(2x) +(2x+3)+(2x+5)= 56
6x+8= 56
6x = 56-8
6x = 48
x = 48/6
x = 8
Three sides are
2x, 2x+3, 2x+5
= 2(8),2(8)+3,2(8)+5
= 16,16+3,16+5
= 16,19,21