A triangle having a perimeter 56 units and its sides are 2 x 2 X + 3 and 2 X + 5 find the respective area of the sides of the triangle
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sum of all sides of triangle is its perimeter
2 X + 2 X + 3 + 2 X + 5 =56
6X + 8 is equal to 56 units
6Xis equal to 48
X=8
sides :
2x=12units
2x+3=15units
2x+5=17units
respectively
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2 X + 2 X + 3 + 2 X + 5 =56
6X + 8 is equal to 56 units
6Xis equal to 48
X=8
sides :
2x=12units
2x+3=15units
2x+5=17units
respectively
hope it is helpful to you :)
mark as brainliest
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