A triangle PQR,where pq=9cm, qr=12cm and pr=15cm, is rotated about the side qr to trace out a cone. find the volume of cone
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Now, the triangle is rotated around QR which is a side forming the right angle.As a result a right circular cone is formed in which height h = QR = 12 cm, r = 9 cm and the slant height l = 15 cm. = 324*pi cm^3. = 216* pi cm ^2. In ∆ PQR , PQ=9 cm, QR =12 cm, and PR= 15 cm. , PQ^2+QR^2= 9^2+12^2= 225.
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