Question

A Triangle whose base is 13 cm and another two sides are 6.5 cm. find its area by Heron's rule.

Answer 1

$\huge\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R}}}}$

Answer 2

$\huge{\boxed{\mathcal\pink{\fcolorbox{red}{white}{Answer}}}}$

So As per heron's formula

$S = \frac{a + b + c}{2}$

$S = \frac{6.5 + 6.5 + 13}{2} = \frac{26}{2} = 13$

${\bold{\large{\green{\boxed{S=13}}}}}$

Formula :

$= \sqrt{s(s - a) (s - b) (s - c)}$

$= \sqrt{13(13 - 13) (13 - 6.5) (13 - 6.5)}$

$\sqrt{13 \times 0 \times 6.5 \times 6.5} = 0$

hope it help ❣