Math, asked by ASingh5398, 10 months ago

A triangle whose sides are 3cm, 4cm and 5cm is revolved about the sides containing 5cm.Find the volume of the solids so formed?

Answers

Answered by awdhutasha84
3

Answer:

volume of solid so formed is 60

Answered by amitnrw
0

volume of the solids so formed = 9.6π cm³ or  30 cm³

Step-by-step explanation:

Right angle triangle is revolved about the hypotenuse BC, the figure so formed is a double cone.

Attached is figure

In triangle ABC,

AB = 3 cm

AC = 4 cm

BC = 5 cm

OB = h₁

OC = h₂

OA = OD = r

h₁ + h₂  = 5

3² =h₁²  + r²

4² = h₂² + r²

=> 4² - 3² = h₂² - h₁²

=> 16- 9 = (h₂+ h₁)(h₂ - h₁)

=> 7 = 5(h₂ - h₁)

=> h₂ - h₁ =7/5

h₁ + h₂  = 5

=> h₁ = 9/5

=> h₂ = 16/5

3² =h₁²  + r²  or 4² = h₂² + r²

=> r² = 9 - (81/25)   or 16 - (256/25)

=> r² = 144/25

=> r = 12 /5

Total Volume = Volume of both cone

= (1/3)π (12/5)² * (9/5)  + (1/3)π (12/5)² * (16/5)

= ( (1/3)π 144 / 5

= 48 π / 5

= 30 cm³

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