A triangle with sides 13 cm 14 cm and 15 cm is inscribed in a circle. The radius of the circle is
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Concept:
The relation between the inscribed triangle and the circle is given by:
R = (a b c) / 4Δ
Given:
We are given the sides of the triangle as 13 cm, 14 cm and 15 cm.
Find:
We need to find the radius of the circle.
Solution:
We have the sides of triangle as:
a = 13 cm
b = 14 cm
c = 15 cm
So, the area of triangle will be:
Area = Δ = √s( s - a)( s - b)( s - c).
s = a + b + c / 2 = (13 + 14 + 15) / 2 = 42 / 2 =21
Δ = √21( 21 - 13)( 21 - 14)( 21 - 15).
Δ = √21( 8 )( 7 )( 6 ).
Δ = √7056
Δ = 84 square units.
Now, we know that the radius of the circle in which a triangle is inscribed will be:
r = (a b c) / 4Δ
r= ( 13 × 14 × 15) / 4(84)
r = 8.125 cm.
Therefore, the radius of the circle is 8.125 cm.
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