A triangle with sides in the ratio 3:4:5 is inscribed in a circle of radius 3cm.what is the area of triangle?
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sum of angles of triangle is 180 degree
Triangle with sides in the ratio is 3:4:5
3x+4x+5x=189
12x=180
x=180/12
x=15
3x =3×15=45degrees
4x=4×15=60degrees
5x=5×15=75 degree
let ABC be triangle
AB =15cm
BC=60cm
CA=75cm
BC be base of triangle
AB be height
area of triangle =1/2×base×height
=1/2×60×15
=450cm
Triangle with sides in the ratio is 3:4:5
3x+4x+5x=189
12x=180
x=180/12
x=15
3x =3×15=45degrees
4x=4×15=60degrees
5x=5×15=75 degree
let ABC be triangle
AB =15cm
BC=60cm
CA=75cm
BC be base of triangle
AB be height
area of triangle =1/2×base×height
=1/2×60×15
=450cm
Bhavs3:
I right or not idont know
plz once check it again
can u think in iit level it is correct or not
Answered by
0
Answer:
Step-by-step explanation:-
sum of angles of triangle is 180 degree
Triangle with sides in the ratio is 3:4:5
3x+4x+5x=189
12x=180
x=180/12
x=15
3x =3×15=45degrees
4x=4×15=60degrees
5x=5×15=75 degree
let ABC be triangle
AB =15cm
BC=60cm
CA=75cm
BC be base of triangle
AB be height
area of triangle =1/2×base×height
=1/2×60×15
=450cm
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