A triangles is formed bt the lines y+x-6=0, 3y-x+2=0 and 3y=5x+2. find the coordinates of its orthocentre.
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Let ΔABC be formed by the intersection of lines:
Then the coordinates of the vertices of triangle can be found as:
Point A can be found by intersection of lines 1 and 2.
Equating the values of x,
Point A = (5, 1)
Point B can be found by intersection of lines 1 and 3.
Equating the values of x,
Point B = (2, 4)
Point C can be found by intersection of lines 2 and 3.
Equating the values of x,
Point C = (–1, –1)
Thus the triangle ABC is:
where H is the orthocenter. (Orthocenter is the point of intersection of altitudes)
աas tɦɨs aռsաɛʀ ɦɛʟքʄʊʟ .....
քʟʐ ʍaʀҡ as ɮʀaɨռɨɛst...
Then the coordinates of the vertices of triangle can be found as:
Point A can be found by intersection of lines 1 and 2.
Equating the values of x,
Point A = (5, 1)
Point B can be found by intersection of lines 1 and 3.
Equating the values of x,
Point B = (2, 4)
Point C can be found by intersection of lines 2 and 3.
Equating the values of x,
Point C = (–1, –1)
Thus the triangle ABC is:
where H is the orthocenter. (Orthocenter is the point of intersection of altitudes)
աas tɦɨs aռsաɛʀ ɦɛʟքʄʊʟ .....
քʟʐ ʍaʀҡ as ɮʀaɨռɨɛst...
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