Question

find two consecutive even numbers such that five sixth of the greater exceeds three fourth of the smaller by 6

Answer 1

$let \: no. \: are \: x \: and \: x + 2 \\ \frac{5}{6} (x + 2) = \frac{3}{4}x + 6 \\4 (5x + 10) = 6(3x + 24) \\ 20x + 40 = 18x + 144 \\ 2x = 104 \\ x = 52 \\ x + 2 = 54$

Answer 2

consecutive even nos. = x, x+2[tex](x) \frac{3}{4} + 6 = (x+2) \frac{5}{6} \\ \\ \frac{3x+24}{4} = \frac{5x+10}{6} \\ \\ 9x+72 = 10x +20 \\ \\ so, x=52, x+2=54[/tex]