A triangular field has sides 210m 180m and 230m long how many meteres of wire is required to fence the field
Answers
Given :-
Sides of the triangular field are –
- 210 m
- 180 m
- 230 m
To Find :-
- Length of wire which is required to fence that field
Solution :-
~Here , we’re given the sides of a triangle and we need to find the wire required to fence the field . When we fence a field we need to find the perimeter according to the shape of field .
⇒ As we know that ,
Perimeter of Triangle = Sum of all sides
*Let’s solve by putting the values !
→ 210 m + 180 m + 230 m
→ 210 + 410 m
→ 620 m
Therefore ,
The length of wire required to fence the triangular field is 620 m .
More formulas :-
- Perimeter of Square = 4( Side )
- Perimeter of Rectangle = 2 ( l + b )
- Perimeter of Rhombus = 4( Side )
- Perimeter of Equilateral Triangle = 3( Side )
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620 m
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- Triangular field of sides 210m, 180m and 230m.
- Metres of wire required to fence the field.
- Perimeter of triangle = sum of all the sides of triangle.
- For finding the length of the wire required to fence the triangular field of sides 210m, 180m and 230m we have to find out the perimeter of the triangle which is calculate by adding all the sides of the triangle.
Let's find out the length of the wire needed by putting the formula of perimeter of triangle.
Length of wire = Perimeter of triangle.
Length of wire = sum of all sides.
Length of wire = (210 + 180 + 230)m
Length of wire = 620 m
Hence, 620m long wire is required to fence the triangular field of sides 210m , 180m and 230m.
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