Question

A triangular park ABC has sides 120m,80m,50m. A gardener Santosh has to put fence all around it and also plant grass inside. How much area does he need to plant? Also find the length of wire required to fence the park.

Answer 1

length of wire needed for the fencing=perineter of park - width of gate
250-3m= 247
cost if fencing=20x247
=4940

hope it helps

Answer 2

Answer:

247m

Step-by-step explanation:

For finding the area of the park, we have

               2s= 50m + 80m + 120m =250m

i.e.,             s= 125m

Now,          s - a = [125-120] m = 5m [a],

                  s - b = [125-80] m = 45m [b],

                  s - c = [125-50] m = 75m [c].

Therefore, area of the park = √s[s-a] [s-b] [s-c]

                                              = √125 × 5 × 45 × 75 m²

                                              = 375√15 m²

Also, perimeter of the park = AB + BC + CA = 250m

Therefore, length of the wire needed for fencing = 250m-3m[ to be left for the gate]

                                                                                 = 247m

So the length of wire required is 247m.

PLEASE MARK AS BRAINLIEST....