Question

a triangular peice of land has one of its angle equal to 90 decree . the area of the land is 330 sq m if one aide adjacent to right angle is11 m what are the lenth of other two sides

Answer 1

ar. of right triangle is 1/2*base*hight
so. a. t. q.
1/2*11*second side = 330
second side = 330*2/11
= 60m
by Pythagoras theorem
p2+b2 = h2
so. h2 = (60)2+(11)2
h = √3600+121
= √3721
= 61m

Answer 2

Adjacent side is 11m
Area of triangle= base×height/2
330=base×11/2
Base=330×2/11
Base=60cm
..... By pythagorean theorem
(Hypothesis)^2= (adjacent)^2+(base)^2
(Hypothesis)^2 = (11)^2 +(60)^2
(Hypothesis)^2 =121 +3600
(Hypothesis)^2 = 3721
Hypothesis =61cm
The two sides are 61cm ,60cm