A trolley is accelerating down an inclined plane of angle theta with acceleration gsin theta
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The trolley of mg parallel to the surface of the inclined plane which is mg sin(theta).
When it comes to theta, it is the angle of incline.
Since, trolley is simply to begin the motion it actually experiences completely limiting the frictional force. Then the question will be ma=mg sin(theta)-(mu) mgcos(theta).
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A trolley is accelerating down an inclined plane of angle theta with acceleration mg sin-theta.
HERE THEETA IS THE ANGLE OF INCLINATION...
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