The area of rhombus is 480cm square and one of its diagonals measures 48cm.find a.length of other diagonal.b) length of each of its sides.c)its perimeter
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10
"The area of the rhombus = 480 sq cm
Diagonal d1 = 48 cm.
Diagonal d2 = ? cm.
Area of rhombus = d1*d2/2 = 36*d2/2 = 480, or
i) d2 = 480*2/48 = 20 cm.
Side of rhombus =[(d1/2)^2+(d2/2)^2]^0.5 = [48^2+20^2]^0.5
= [576+100]^0.5
= 676^0.5
= 26 cm.
ii) Diagonal d2 = 48 cm, sides = 26 cm.
iii) Perimeter=4*26=104 cm
"
Answered by
26
Find the length of the other diagonal:
Area of a rhombus = 1/2(Diagonal 1 x Diagonal 2)
480 = 1/2 (48 x Diagonal 2)
48 x Diagonal 2 = 960
Diagonal 2 = 20 cm
Find the length of its side:
half of each diagonal and the side make a right angle triangle
a² + b² = c²
(20÷2)² + (48÷2)² = c²
c² = 676
c = 26 cm
Find the perimeter:
Perimeter = 4 x Length
Perimeter = 4 x 26 = 104 cm
Answer: (a) Diagonal = 20 cm (b) length = 26 cm (c) Perimeter = 104 cm
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