Question

A trolley of mass 8 kg is standing on a frictionless surface inside which an object of mass 2 kg is suspended. A constant force F starts acting on the trolley as a result of which the string stood at an angle of 370 from the vertical. Then : (1) acceleration of the trolley is 40/3 m/sec2 . (2) force applied in 60 N (3) force applied is 75 N (4) tension in the string is 30 N

Answer 1

Answer:

Option (3) Force applied is 75 N

Explanation:

Force F is acting on the whole system

F = (8 + 2) a

or, F = 10a

Again w.r.t. the trolley, the mass will be in the state of rest acceleration of the block will be a agian

Therefore

F' = 2a

Tcos37° = 2g

or, T × (4/5) = 2g

or, T = 2.5g = 25 N

Also

Tsin37° = F'

or 2.5g × (3/5) = 2a

or a = 7.5 m/s²

Therefore F = 10 × 7.5 = 75 N

Thus the correct option is option (3)