Question

A trolley while going down an inclined plane has an acceleration of 2cm/s2.what will be its velocity 3 s after the start

Answer 1

U=0
Acceleration= 2cms/2
Time taken = 3 sec
According to second equation of motion ,
V=u+at
After 3 sec from start v=0 +0.02 ×3
=0.06 m/s

Answer 2

Solution,

Here, we have

Initial velocity of the trolley, u = 0 (As starts from rest)

Acceleration of the trolley, a = 0.02 m/s²

Time taken by the trolley, t = 3 seconds

To Find,

Final velocity of the trolley, v = ?

According to the 1st equation of motion,

We know that,

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ v = 0 + 0.02 × 3

⇒ v = 0.02 × 3

⇒ v = 0.06 m/s

Hence, the final velocity of the trolley is 0.06 m/s.