Question

A trolley while going down an inclined plane has the acceleration of 2m s-².What distance will it cover in 10s of start.​

Answer 1

➜Given :

• Initial velocity = U = 0
• Acceleration = A = 2m/s-²
• Time = 10s

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➜To Find :

• Distance covered after 10s of start = ?

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➜Formula used :

First equation of motion :

${\red{\bigstar \: {\orange{\underbrace{\underline{\overbrace{\overline{\bf{V = U + at}}}}}}}}}$

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➜Solution :

${\maltese{\underline{\bf{Here,}}}}$

U = 0

A = 2m/s-²

T = 10s

V = ?

${\maltese{\underline{\bf{Than,}}}}$

${\leadsto{\sf{V = U + at}}}$

${\leadsto{\sf{V = 0 + 2(10)}}}$

${\leadsto{\sf{V = 0 + 20}}}$

${\large{\purple{:{\mapsto{\underline{\boxed{\bf{V = 20 m}}}}}}}}$

${\maltese{\underline{\bf{Hence,}}}}$

${\red{\underline{\purple{\underline{\boxed{\red{\mathfrak{Distance \: Covered = 20m}}}}}}}}$

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