Question

A trolley, world going down an inclined plane has an acceleration of 2 cm s-2 what will be its velocity 3 s after the start?​

Answer 1

$\mathfrak\red{Answer:--}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

${\underline{\boxed{\green{\bf{Given:}}}}}$

Acceleration of Trolley a = m/s^2 = 0.02ms^2

Initial speed of trolley , u = 0 (As trolley start from rest)

Time taken by trolley , t = 3second

⠀⠀

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

─────────────────────────────

⠀⠀⠀⠀

⠀⠀⠀⠀

${\underline{\boxed{\green{\bf{To \: \: find:}}}}}$

Final Speed , v = ??

⠀

${\underline{\boxed{\blue{\bf{Formula \: to \: be \: used:}}}}}$

1st Equation of Motion ,

i.e, ⠀⠀⠀v = u + at

⠀

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃─────────────────────────────

⠀

⠀

${\underline{\boxed{\green{\bf{Solution:}}}}}$

Putting all the values, we get

⠀⠀⠀⠀⠀v = u +at

⇒v = 0 + 0.02 × 3

⇒v = 0.02 × 3

⇒v = 0.06 m/s

⠀

Hence the final Velocity of Trolley is 0.06m/s.

⠀

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃

─────────────────────────────⠀⠀⠀

⠀⠀⠀

⠀⠀⠀

Important Terms:-

Final Speed :- Final speed is that speed which is acquired by the body after its start .

↦It is denoted by v.

When a body finally comes its rest, its final speed is zero.

Answer 2

Answer:

Given :-

• A trolley while going down an inclined plane has an acceleration of 2 cm/s².

To Find :-

• What is the velocity of 3 seconds after the start.

Formula Used :-

$\clubsuit$ First Equation Of Motion Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{v =\: u + at}}}\: \: \: \bigstar$

where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• t = Time Taken

Solution :-

First, we have to convert the acceleration cm/s² into m/s² :

$\implies \bf Acceleration =\: 2\: cm/s^2$

$\implies \sf Acceleration =\: \dfrac{2}{100}\: m/s^2$

$\implies \sf\bold{\purple{Acceleration =\: 0.02\: m/s^2}}$

Hence, the acceleration of a trolley is 0.02 m/s² .

Given :

• Initial Velocity = 0 m/s [Note : Initial Velocity = 0, as the trolley begins from the rest position. ]
• Acceleration = 0.02 m/s²
• Time Taken = 3 seconds

According to the question by using the formula we get,

$\implies \bf v =\: u + at$

$\implies \sf v =\: 0 + (0.02)(3)$

$\implies \sf v =\: 0 + 0.02 \times 3$

$\implies \sf v =\: 0 + 0.06$

$\implies \sf\bold{\red{v =\: 0.06\: m/s}}$

$\therefore$ The required velocity of the trolley is 0.06 m/s .