A trolly while going down inclined plane has an acceleration of 4ms2 what distance will it cover los after start
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Answer:
The "velocity of the trolley" at 3 s is 0.06 m/s .
Explanation:
Given data:
Acceleration, a = 2 cm/s^2 = 0.02 m/s^2
To find:
Velocity after 3 s = ?
Solution:
The trolley is on the inclined plane,
Thereby, the first equation of motion is to be applied to calculate velocity after 3 sec.
Therefore, we have,
t = 3 sec
u = 0
a=2m/s^2= 0.002m/s^2
v=u+at
v=0+(0.02*3)
v=0.06 m/s
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