Question

a truck accelerates a constant rate of change of velocity in 5 sec 10 m/s to 25 m/s on ahigh way what is the acceleration and how far is the truck go in this interval of time ? give a graphical solution​

Answer 1

Answer:

umm a=0 think so not confirmed

Explanation:

Answer 2

Initial Velocity, u = 10 m/s

Final Velocity, V = 25 m/s

time duration, t = 5 sec

acceleration, a = change in velocity upon time

a = ( v – u ) / t

a = ( 25 – 10 ) / 5

a = 15 / 5

a = 3 m/s²

Using second equation of motion

s = ut + 1/2 at²

s = 10(5) + 0.5 ( 3 ) (5)²

s = 50 + 1.5 × 25

s = 50 + 37.5

s = 87.5 m

Hope the solution is clear to!!