Question

A truck carries a box of mass m = 50 kg on aflat horizontal rough surface with μ = 0.3 . It is crossing a circular track of radius 27 m. What is the maximum speed of truck so that the box does not slide from truck while moving on a circular path ?

Answer 1

Answer:

9m/s

as we get from the free body diagram that the centrifugal force is equal to the frictional force as the linear acceleration of the object is zero.

so we get 2 equations and 2 variables.

BOOM WE ARE DONE

Answer 2

The maximum speed of truck is 9 m/s.

Explanation:

Given that,

Mass of truck = 50 kg

Radius = 27 m

Frictional coefficient = 0.3

We need to calculate the maximum speed of truck

Frictional force equal to centripetal force

$F_{f}=F_{c}$

$\mu mg=\dfrac{mv^2}{r}$

$\mu\times mg=\dfrac{mv^2}{r}$

Put the value into the formula

$v^2=0.3\times10\times27$

$v=\sqrt{0.3\times10\times27}$

$v=9\ m/s$

Hence, The maximum speed of truck is 9 m/s.

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Topic : frictional force

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