Question

A truck covers 40 km with an average speed of 80km/h. then it travels another 40 km with an average speed of 40 km/h. the average speed of the truck for the total distanced covered

Answer 1

Hey mate!

Here's your answer!!
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Time taken for 1st 40 km (t1)

$= \frac{40}{80} = \frac{1}{2} hr$

Time taken for 2nd 40 km (t2)

$= \frac{40}{40} = 1 \: hr$
Average speed of the truck for the total distance covered is,

$= \frac{total \: distance \: travelled}{total \: time \: taken}$


$= \frac{40 + 40}{ \frac{1}{2} + 1 }$

$= \frac{80}{3} \times 2$

$= \frac{160}{3} = 53.33 \: km |h$

Therefore, the average speed of the truck for the total distance covered is 53.33 km/h.
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✪ Hope it helps you! ✪

#BE BRAINLY

Answer 2

Dear Student,

◆ Answer -

v = 53.33 km/h

● Explanation -

# Given -

d1 = 40 km

v1 = 80 km/h

d2 = 40 km

v2 = 40 km/h

# Solution -

Total distance covered is -

d = d1 + d2

d = 40 + 40

d = 80 km

Total time taken is -

t = t1 + t2

t = d1/v1 + d2/v2

t = 40/80 + 40/40

t = 1/2 + 1

t = 1.5 h

So average speed will be -

v = d/t

v = 80/1.5

v = 53.33 km/h

Hence, average speed is 53.33 km/h.

Thanks dear. Hope this helps you..