Question

A truck running at 72 km/h is brought to rest over a distance of 25m calculate the retardation and the time which brakes are applied

Answer 1

here u= 72km/ hr = 72×5/18=20m/s. v =0. s = 25 m. v^2-u^2 = 2as. -400=2a×25 so a = -8m/s^2 and for time v=u+ at so 0=20-8t = t= 2.5 s

Answer 2

Answer:

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