Question

a truck is moving with a velocity of 20m/s in north direction.it has a uniform acceleration of 5m/s².Calculate final velocity of truck after travelling a distance of 50m​

Answer 1

$\overline{\underline{\boxed{\sf GIVEN \darr}}}$

A truck is moving with a velocity of 20m/s in north direction.it has a uniform acceleration of 5m/s².Calculate final velocity of truck after travelling a distance of 50m

$\overline{\underline{\boxed{\sf SOLUTION \darr}}}$

Given that :

Uniform Velocity (u) = 20 m/s

Acceleration (a) = 5 m/s²

Distance (S) = 50 m

Final Velocity (v) = ?

To get the final velocity we need to apply the third equation of motion i.e.

• v² = u² + 2aS

Putting the values we get

• v² = (20)² + 2 × 5 × 50

• v² = 400 + 500

• v² = 900

• v = √900

• v = 30

Therefore, final velocity of the truck is 30 m/s

$\overline{\underline{\boxed{\sf KNOW \:MORE \darr}}}$

First equation of motion :

• v = u + at

Second equation of motion :

• S = ut + 1/2at²

Third equation of motion :

• v² = u² + 2aS

Answer 2

Step-by-step explanation:

Given :

• Initial velocity (u) = 20 m/s
• Acceleration (a) = 5 m/s²
• Distance covered (s) = 50 m

To find :

• Final velocity (v)

Solution :

Using Kinematics:

=> v² - u² = 2as

We get:

=> v² - 20² = 2(5)(50)

=> v² - 400 = 500

=> v² = 500 + 400

=> v² = 900

=> v = √900

=> v = 30 m/s

Verification :

=> v² - u² = 2as

=> 30² - 20² = 2(5)(50)

=> 900 - 400 = 500

=> 500 = 500

∴ L.H.S = R.H.S

• Hence, the final velocity of the truck is 30 m/s.