A truck of 5000kg moving with a velocity of 54 km h - 1 hits against a hill and comes to in 2 sec .how much force is exerted on the truck by the hill?
Answers
Answered by
13
m= 5000kg
v1= 54km/h= 15m/s
t= 2 sec
v2= 0
Force?
v2= v1+ at
0 = 15+2a
a=-15/2
a= -7.5 m/s^2
Now F= ma
F= 5000 x 7.5
F=37500 kgm/s
F= 37500 N in the opposite direction
v1= 54km/h= 15m/s
t= 2 sec
v2= 0
Force?
v2= v1+ at
0 = 15+2a
a=-15/2
a= -7.5 m/s^2
Now F= ma
F= 5000 x 7.5
F=37500 kgm/s
F= 37500 N in the opposite direction
Answered by
3
F = mv/t
= 5000 × (54 × 5/18) / 2
= 37.5 kN
Force exerted by truck on hill is 37.5 kN
[Note: I converted 54 kmph to m/s]
= 5000 × (54 × 5/18) / 2
= 37.5 kN
Force exerted by truck on hill is 37.5 kN
[Note: I converted 54 kmph to m/s]
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