A truck of mass 1000kg increases its speed from 36 km per hour to 72 km per hour . Find the increase in its kinetic energy.
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Answered by
34
72 kmph = 72 × 5/18 m/s = 20 m/s
36 kmph = 36 × 5/18 m/s = 10 m/s
Increase in kinetic energy = 0.5 m (v² - u²)
= 0.5 × 1000 kg × [(20 m/s)² - (10 m/s)²]
= 150 × 10³ J
= 150 kJ
Increase in its kinetic energy is 150 kJ
36 kmph = 36 × 5/18 m/s = 10 m/s
Increase in kinetic energy = 0.5 m (v² - u²)
= 0.5 × 1000 kg × [(20 m/s)² - (10 m/s)²]
= 150 × 10³ J
= 150 kJ
Increase in its kinetic energy is 150 kJ
Answered by
21
The answer to your question is attached below as q 9. From Selina physics class
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