Question

A truck of mass 1500 kg is travelling at a steady speed of 45 m/s against a resistive force of 3000 N. What is the minimum power that the engine has to deliver to the wheels?​

Answer 1

Answer:

Explanation:

kinetic enrgy =0.5mv^2

                      =0.5*1500*(45)^2

                      =15,18,750 joule

Energy used = force x distance = 3000 x 45

                                                    = 15000 joule =15 kj

minimum power = Energy used/time taken

                           = 15 kj is the power minimum that engine has given