A truck of mass 2000 kg encounters a constant frictional force of 800 N as it moves on a straight road. The speed of the truck increases from 20 ms−1 to 30 ms−1 as it covers a distance of 400 m. What is the thrust generated by the truck’s engine?
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Energy of truck=lost energy due to friction + K.E. gain
Kinetic enery can be calculated using formula,
K.E = ½ m vsquare
In this case, as speed of the truck increases from 20 ms−1 to 30 ms−1.
So, Vsquare = (30*30 – 20*20)
By using frictional force of 800N to cover 400 m distance, we can calculate Wf.
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