A truck of mass 2800 kg is moving with a speed of 15m/s a frictional retarding force of 500 n and forward force of 1200 n are acting on it then in 10 sec it shall travel a distance of
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mass of truck = 2800kg
speed of truck = 15 m/s
friction force = 500N
forward force = 1200 N
Average Force = 700 N
Force = mass × acceleration
700 N /2800 kg = acceleration= 0.25 m/s^2
u=15m/s
a=0.25m/s^2
t=10sec
s=ut+ 1/2.a×t^2
s=150+1/2×(0.25)×100
s=162.5 m
speed of truck = 15 m/s
friction force = 500N
forward force = 1200 N
Average Force = 700 N
Force = mass × acceleration
700 N /2800 kg = acceleration= 0.25 m/s^2
u=15m/s
a=0.25m/s^2
t=10sec
s=ut+ 1/2.a×t^2
s=150+1/2×(0.25)×100
s=162.5 m
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