A truck of mass 3000 kg is moving at 10 metre per second and is acted upon by two forces a forward force of 1000 newton due to engine and retarding force of 400 friction what is the rate at which it is gaining speed
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Explanation:
mass equal to 3000 kg
speed equal to 10 metres per second
1000 N acting due to the engine and retarding force of 400 Newton
therefore resultant force is equal 2000 Newton - 400 = 600 Newton due to the engine
force is equal to mass into acceleration
600 newton is equal to 3000 kg multiplied by a
therefore a is equal to 1 by 5 or 0.2
therefore the acceleration is 0.2 per second square
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