Question

An object of mass 2 kg is sliding with a constant velocity of 4 m/s on a
frictionless horizontal table. The force required to keep this object moving with
the same velocity is
(2) 32 N (6) 8N (c) 2N (d) ON

Answer 1

$\huge{\bold{\underline{\underline{....Answer....}}}}$

$\huge{\bold{\underline{Given:-}}}$

m = 2 kg.

v = 4 m/s.

$\huge{\bold{\underline{Explanation:-}}}$

It is given it is moving on friction less surface.

As it is moving on friction less surface there is no resisting force (Frictional force) which will act on the object.

So, there is will be no change in velocity

(As the there is no external force acting on it.)

${ \therefore}$ acceleration will be Zero. as velocity is constant.

$\large{a = \frac{dv}{dt}}$

$\large{a = \frac{d(4 m/s)}{dt}}$

Here 4 m/s is a constant.

$\large{a = 0 m/s^2}$(Differentiating a constant gives Zero)

Applying Newton's second law of motion.

$\large{F = ma}$

Substituting the values

$\large{F = m \times 0}$

$\large{F = 0N}$

$\huge{\boxed{\boxed{F = 0N}}}$

So, 0N Force will be applied to move the object with the same velocity on friction less surface.