A truck of mass 500 kg travelling at 40 m/s is brought to rest by applying the brakes. The truck comes to rest after travelling 20 m, after applying the brakes. What is the kinetic energy of the truck?
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Kinetic Energy at first= 1/2mv^2 = 1/2*500*1600 = 400000J
KE after stopping = 0 (velocity is 0)
KE after stopping = 0 (velocity is 0)
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