Question

A truck of mass 5000 kg rolls down a hill starting from rest. If it covers 200 m in 10 s then force acting on it will be

Answer 1

it's initial velocity is 0 m/s
final velocity =distence /time
=200/10
=20 m/s
acceleration =(final velocity -initial velocity )/time taken
a=(20-0)/10
=20/10
=2m/s^2
force = mass×acceleration
=5000×2
=10000N