A truck of mass 5000 kg rolls down a hill starting from rest. if it covers 200 m in 10 s then force acting on it will be (a) 200 n (b) 20000 n (c) 2000 n (d) 500 n
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It starts from rest, so u = 0
travels 200m, so s = 200m
time = 10s
let the acceleration = a m/s²
v = u +at = 0 + a×10 = 10a m/s
we know that
v² - u² = 2as
⇒ (10a)² - 0 = 2×a×200
⇒ 100a² = 400a
⇒ 100a = 400
⇒ a = 400/100
⇒ a = 4 m/s²
mass = 5000kg
force = ma = 5000×4 = 20,000 N = 20 kN
travels 200m, so s = 200m
time = 10s
let the acceleration = a m/s²
v = u +at = 0 + a×10 = 10a m/s
we know that
v² - u² = 2as
⇒ (10a)² - 0 = 2×a×200
⇒ 100a² = 400a
⇒ 100a = 400
⇒ a = 400/100
⇒ a = 4 m/s²
mass = 5000kg
force = ma = 5000×4 = 20,000 N = 20 kN
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