Question

A truck of mass 5000 kg rolls down the hill starting from rest. If it covers 200 m in 10 sec then force acting on it will be

Answer 1

5000 * 200 / 10 is the answer which is 2500 N

Answer 2

Solution :-

• Initial velocity = 0 $\dfrac{m}{s}$

• Time taken = 20 seconds

☆Distance covered by stone = 400m.

According to second equation :-

${\boxed{\large{\bold{s\:=\:ut\:+ \dfrac{1}{2}{at}^{2}}}}}$

we have :-

$\hookrightarrow\:400\:=\:0\:×\:20\:+ \dfrac{1}{2}\:×\:a\:×\: {(20)}^{2}$

$\hookrightarrow\:400\:=\:200a$

$\hookrightarrow\:a\:=\:2 \dfrac{m}{s}^{2}$

Now , force = Mass × acceleration

⠀⠀⠀⠀⠀⠀⠀⠀= 7000 × 2

⠀⠀⠀⠀⠀⠀⠀⠀= 14000N

Therefore force = 14000 N