Question

A truck of mass 5000 of traveling at 40 m/s is brought to rest by applying brakes. the truck comes to rest after traveling 20m after the application of brakes.what is the kinetic energy of the truck?
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Answer 1

Answer:

Here v=0 m/s and u= 40m/s

S= 20 m

V2-u2= 2as

-(20)2 =2x20a

-400/40=a

-10m/s2= a

K.E= ½ m v2

=1/2x 5000x40 x40

5000x20x40

= 4x 106J

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