Question

A truck of mass 5000kg rolls down a hill starting from rest if it covers a distance of 200metres in10 sec then force acting on it would be

Answer 1

f=ma


but
v=d/t
v=200/10
v=20ms'

f=ma
f=m(v-u)/t
f=5000(20-0)/10
f=5000(20)/10
f=5000(2)
f=100000N

Answer 2

force acting on them ?

here =mass 5000

distance =20m

time 10sec.

so, f =ma

v =d/t  = 200/10  =20m/s

v= u+at  ,,   their initial velocity =0

hence v=at

20=a*10

then a=2

f=ma  5000*2 =hence force acting on them would be =10000