Question

A truck of mass 5000kg rolls down on hill starting from rest. If it covers 200m in 10 sec then force acting on it will be

Answer 1

we know that force =mass×acceleration
mass=5000 , acceleration = v-u/t
u=0 v=distance/time
=200/10=20m/s
acceleration=20-0/10=2m/s^2
force=5000×2=10000N

Answer 2

m = 5000 kg
t = 10s
u = 0m/s

v = distance/time

= 200/10

= 20m/s

acceleration = final velocity - initial velocity /time

= 20 - 0/10

=2m/s²
----------------------------
F =ma
= 5000 x 2

= 10,000N