a truck running along a straight line increases its speed uniformly from 30m/s to 60m/s over a time interval 1 min . what is the distance travelled during this interval?
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Answered by
15
v=60m/s
u=30m/s
t=1 min = 60 seconds
To find distance travelled (s)
Since v=u+a×t
So 60=30+a×60
60-30=60 a
30=60 a
30÷60=a
0.5=a
a=0.5m/s square
Now, s=ut+1/2a×t×t
s=30×60+1/2×0.5×60×60
s=1800+1/2×0.5×3600
s=1800+0.5×1800
s=1800+900
s=2700 m
s=2.7 km (1km=1000m)
Hence the truck travelled 2.7km in that time interval.
u=30m/s
t=1 min = 60 seconds
To find distance travelled (s)
Since v=u+a×t
So 60=30+a×60
60-30=60 a
30=60 a
30÷60=a
0.5=a
a=0.5m/s square
Now, s=ut+1/2a×t×t
s=30×60+1/2×0.5×60×60
s=1800+1/2×0.5×3600
s=1800+0.5×1800
s=1800+900
s=2700 m
s=2.7 km (1km=1000m)
Hence the truck travelled 2.7km in that time interval.
Answered by
3
Answer:2700m
Explanation:
2.7km
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