Question

A truck running along a straight road increases its speed uniformly from 15m sec^-1 to 30m sec^-1 over a time interval of I minutes . Find the acceleration .Also find the distance travelled by the truck during this interval.

Answer 1

acceleration = a
final velocity=v
initial velocity=u
time=t
distance=s

acceleration = (final velocity- initial velocity)/time
a=(v-u)/t
final velocity=30m/s
initial velocity=15m/s
time=1minute=60sec

according to the formulla------

a=(30-15)/60
 =5/60
 =1/12
 =0.834m/s^2


2*a*s=(v^2) - (u^2)
2*0.834*s=(30^2) - (15^2)
1.668*s=900-225
1.668*s=675
s=675/1.668
s=404.67m

Answer 2

Answer:

Acceleration = a

final velocity=v

initial velocity=u

time=t

distance=s

acceleration = (final velocity- initial velocity)/time

a=(v-u)/t

final velocity=30m/s

initial velocity=15m/s

time=1minute=60sec

according to the formulla------

a=(30-15)/60

 =5/60

 =1/12

 =0.834m/s^2

2*a*s=(v^2) - (u^2)

2*0.834*s=(30^2) - (15^2)

1.668*s=900-225

1.668*s=675

s=675/1.668

s=404.67m