a truck starts from a rest and accelerates uniformly at 2.0. at t =10s a stone is dropped by a person standing on the top of the truck then what are the velocity and acceleration of the stone at t=11s
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when the stone is dropped only gravitational force acts on it
at t=11sec
horizontal velocity
v=u+at=velocity at time 10sec
v=0+2*10=20m/s
vertical velocity
v=0+9.8*1
v=9.8m/s
at t=11sec
horizontal velocity
v=u+at=velocity at time 10sec
v=0+2*10=20m/s
vertical velocity
v=0+9.8*1
v=9.8m/s
ashwi2:
then acceleration a=?
it depends on time
when stone is on truck its horizontal acceleration is 2 and vertical acceleration is 9.8
and when in air the horizontal acceleration is 0 and vertical one remain same
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