. A truck starts from rest and accelerate uniformly at 2 m s. Att=10 s, a stone is dropped by a person standing on the top of the truck 6 m high from the ground. The velocity of the stone at t= 11 s is (Take g = 10 m's-2)
(1) V5ms-1
(2) 10/5ms- 1
(3) 20ms-1
(4) 515ms -^1
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Explanation:
(b) When the stone is dropped from the truck, the horizontal force acting on it becomes zero. However, the stone continues to move under the influence of gravity. Hence, the acceleration of the stone is 10 m/s2 and it acts vertically downward
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