A truck starts from rest and rolls down a hill with a constant acceleration. it travels a distance of 400min 20s. find it's acceleration.find the force acting on it if its mass is 7 tonnes.1 tonne =1000kg
Answers
Answered by
37
From the equation,
s = ut+(1/2)at²
u = 0
s= 400 m
t= 20 sec
⇒400 = (1/2) a×(20)²
⇒800 = 400 a
⇒a = 2 m/s²
1 tonne = 1000 kg
so, 7 tonnes = 7000 kg
F = ma = 7000×2 = 14000 N
s = ut+(1/2)at²
u = 0
s= 400 m
t= 20 sec
⇒400 = (1/2) a×(20)²
⇒800 = 400 a
⇒a = 2 m/s²
1 tonne = 1000 kg
so, 7 tonnes = 7000 kg
F = ma = 7000×2 = 14000 N
Answered by
13
☺ Hello mate__ ❤
◾◾here is your answer...
u = 0 m/s
t = 20 s
s = 400 m
According to the second equation of motion:
s = ut + 1/2 at^2
400 = 0 + 1/2 × a × (20)^2
a = (400 × 2 )/400 = 2m/s^2
7 metric tons = 7000 kg
Now,
Force = mass × acceleration
⇒ F= 7000 × 2 = 14000 N
I hope, this will help you.
Thank you______❤
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