Question

a truck starts from rest and Rolls down a hill with a constant acceleration it has a distance of 400 m in 20 seconds find the acceleration find the force acting on it if its mass is 7 tonnes (Hint 1 tonnes =1000kg.)

Answer 1

Initial velocity(u) = 0 m/s.
Distance(s) = 400 m.
Time(t) = 20 s.

Final velocity(v) = 400/20 = 40/2 = 20 m/s.

Acceleration(a) = v-u/t.
a = 20-0/20.
a = 20/20.
a = 1 m/s².

Force(F) = ma.
Mass(m) = 7 tonnes = 7000 kg.

Force = 7000*1.
F = 7000N.

Therefore, the acceleration produced = 1 m/s² and the force acting on it = 7000 N.

Answer 2

☺ Hello mate__ ❤

◾◾here is your answer...

u = 0 m/s

t = 20 s

s = 400 m

According to the second equation of motion:

s = ut + 1/2 at^2

400 = 0 + 1/2 × a × (20)^2

a = (400 × 2 )/400 = 2m/s^2

7 metric tons = 7000 kg

Now,

Force = mass × acceleration

⇒ F= 7000 × 2 = 14000 N

I hope, this will help you.

Thank you______❤

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