Question

a truck starts from rest and Rolls down a hill with constant acceleration .it travels a distance 400m in 20 sec.find its acceleration.find the force acting on it if its mass is 7 tonnes.(1 tone is=1000kg)

Answer 1

u = 0m/s
s= 400m , t= 20sec
using second equation of motion
s= ut+1/2at²
s= 0(20)+1/2(a)(20)²
400 = 0+1/2(a)(400)
400= 200a
a = 400/200 = 2m/s²

mass = 7 tonne = 7(1000) kg => 7000kg
therefore,
force = ma => 7000(2) = 14000 N
hope this helps

Answer 2

☺ Hello mate__ ❤

◾◾here is your answer...

u = 0 m/s

t = 20 s

s = 400 m

According to the second equation of motion:

s = ut + 1/2 at^2

400 = 0 + 1/2 × a × (20)^2

a = (400 × 2 )/400 = 2m/s^2

7 metric tons = 7000 kg

Now,

Force = mass × acceleration

⇒ F= 7000 × 2 = 14000 N

I hope, this will help you.

Thank you______❤

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