a truck starts moving with an initial velocity of 36 km per hour how much distance will it cover in one minute if it moves with a uniform acceleration of 1 M per second square
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Initial Velocity (u) = 36km/h
Time Taken (t) = 1 min
Acceleration (a) = 1 m/s^2
u = 36km/h = 36 * 1000 / 60 * 60 m/s
u = 10 m/s
t = 1 min = 1 * 60 s = 60s
s = ut + 1/2 at^2 [second eq. of motion]
s = (10*60) + 1/2 * 1 * (60)^2
s = 600 + 1/2 * 3600
s = 600 + 1800
s = 2400m
Therefore, the truck covers 2,400m in one minute.
Time Taken (t) = 1 min
Acceleration (a) = 1 m/s^2
u = 36km/h = 36 * 1000 / 60 * 60 m/s
u = 10 m/s
t = 1 min = 1 * 60 s = 60s
s = ut + 1/2 at^2 [second eq. of motion]
s = (10*60) + 1/2 * 1 * (60)^2
s = 600 + 1/2 * 3600
s = 600 + 1800
s = 2400m
Therefore, the truck covers 2,400m in one minute.
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